Chemistry, asked by astha4848, 1 year ago

Definition molarity normality and percentage with example

Answers

Answered by BrainlyWarrior
0
\textbf{Hello Mate}☺☺

\textbf{Question}>>>Definition molarity normality and percentage with example

\textbf{Answer}>>>>

\textbf{Molarity}>>>

Molarity of a solution is defined as the number of the solute dissolved per litre of a solution.It is represented as (M).

Molarity =

\frac{Moles.. of.. solute}{Volume.. of.. solution.. in..litres}

It is convenient to express Volume in cm^3 or mL so that...

Molarity =

\frac{Moles.. of..solute}{Volume.. of.. solution.. in.. mL} x 1000

1 litre = 1000mL.

\textbf{Normality}>>>

Normality of a solution is the number of gram equivalents of the solute dissolved per litre of a solution.It is denoted by (N).

Normality =

\frac{Number..of.. gram.. equivalents..of.. solute}{Volume.. of.. solution.. in.. litres}

or

Normality =

\frac{Number.. of.. gram.. equivalents.. of.. solute}{Volume.. of... solution.. in.. mL} x 1000

where Gram equivalents of solute can be calculated as>>>

Gram equivalents of solute =

\frac{Mass.. of.. solute}{Equivalent.. mass}

\textbf{Example}>>>

➡Calculate the normality of a solution containing 31.5 g of hydrated oxalic acid in 1250 mL of solution.

Solution>>>

Mass of oxalic acid = 31.5 g

Using the Normality formula......

Equivalent of oxalic acid = \frac{31.5}{63}

= 0.5

Volume of solution = 1250 mL

N = \frac{0.5}{1250} x 1000

= 0.4N

\textbf{Mass percentage}>>>

The mass percentage of a component in a given solution is the mass of the component per 100g of the solution.

Mass % of a component =

\frac{Mass.. of..the.. component.. in.. the.. solution}{Total.. mass..of.. the.. solution} x 100

\textbf{Example}>>>

➡If 11 g of oxalic acid are dissolved in 500 mL of solution (density = 1.1 g m\upper{L}^-1 , what is the mass % of oxalic acid?

Solution>>>>

density = 1.1 g m\upper{L}^-1

Mass of solution =( 500mL ) x ( 1.1 g m\upper{L}^-1)

= 500 g

we
Mass of oxalic acid = 11g

Mass % of oxalic acid = \frac{11}{550} x 100

= 2%

\textbf{Be Brainly....}

@karangrover12
Answered by vinshultyagi
3

{\Large{\textbf{\underline{Answer:-}}}}

\textbf{Molarity}

Molarity of a solution is defined as the number of the solute dissolved per litre of a solution.It is represented as (M).

Molarity =

\bf \dfrac{Moles\:of\: solute}{Volume\: of\: solution\: in\:litres}

\textbf{Normality}

Normality of a solution is the number of gram equivalents of the solute dissolved per litre of a solution.It is denoted by (N).

Normality =

\bf \dfrac{Number\: of\: gram\: equivalents\:of\:solute}{Volume\: of\: solution\:in\:mL\:or\:L} ×100

\textbf{Mass percentage}

The mass percentage of a component in a given solution is the mass of the component per 100g of the solution.

Mass % of a component =

\bf \dfrac{Mass\:of\:the\:component\: in\: the\: solution}{Total\:mass\:of\:the\: solution}×100

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