Definition molarity normality and percentage with example
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>>>Definition molarity normality and percentage with example
>>>>
✔>>>
Molarity of a solution is defined as the number of the solute dissolved per litre of a solution.It is represented as (M).
Molarity =
It is convenient to express Volume in cm^3 or mL so that...
Molarity =
x 1000
1 litre = 1000mL.
✔>>>
Normality of a solution is the number of gram equivalents of the solute dissolved per litre of a solution.It is denoted by (N).
Normality =
or
Normality =
x 1000
where Gram equivalents of solute can be calculated as>>>
Gram equivalents of solute =
>>>
➡Calculate the normality of a solution containing 31.5 g of hydrated oxalic acid in 1250 mL of solution.
Solution>>>
Mass of oxalic acid = 31.5 g
Using the Normality formula......
Equivalent of oxalic acid =
= 0.5
Volume of solution = 1250 mL
N = x 1000
= 0.4N
✔>>>
The mass percentage of a component in a given solution is the mass of the component per 100g of the solution.
Mass % of a component =
x 100
>>>
➡If 11 g of oxalic acid are dissolved in 500 mL of solution (density = 1.1 g m , what is the mass % of oxalic acid?
Solution>>>>
density = 1.1 g m
Mass of solution =( 500mL ) x ( 1.1 g m)
= 500 g
we
Mass of oxalic acid = 11g
Mass % of oxalic acid = x 100
= 2%
@karangrover12
>>>Definition molarity normality and percentage with example
>>>>
✔>>>
Molarity of a solution is defined as the number of the solute dissolved per litre of a solution.It is represented as (M).
Molarity =
It is convenient to express Volume in cm^3 or mL so that...
Molarity =
x 1000
1 litre = 1000mL.
✔>>>
Normality of a solution is the number of gram equivalents of the solute dissolved per litre of a solution.It is denoted by (N).
Normality =
or
Normality =
x 1000
where Gram equivalents of solute can be calculated as>>>
Gram equivalents of solute =
>>>
➡Calculate the normality of a solution containing 31.5 g of hydrated oxalic acid in 1250 mL of solution.
Solution>>>
Mass of oxalic acid = 31.5 g
Using the Normality formula......
Equivalent of oxalic acid =
= 0.5
Volume of solution = 1250 mL
N = x 1000
= 0.4N
✔>>>
The mass percentage of a component in a given solution is the mass of the component per 100g of the solution.
Mass % of a component =
x 100
>>>
➡If 11 g of oxalic acid are dissolved in 500 mL of solution (density = 1.1 g m , what is the mass % of oxalic acid?
Solution>>>>
density = 1.1 g m
Mass of solution =( 500mL ) x ( 1.1 g m)
= 500 g
we
Mass of oxalic acid = 11g
Mass % of oxalic acid = x 100
= 2%
@karangrover12
Answered by
3
Molarity of a solution is defined as the number of the solute dissolved per litre of a solution.It is represented as (M).
Molarity =
Normality of a solution is the number of gram equivalents of the solute dissolved per litre of a solution.It is denoted by (N).
Normality =
The mass percentage of a component in a given solution is the mass of the component per 100g of the solution.
Mass % of a component =
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