Question

If x=3 and y=4 find x2+3xy+y2

Answer 1

x²+3xy+y²
if x=3 and y=4,
(3)²+3×3×4+(4)²
=9+36+16
=61
It will help u

Answer 2

$x ^{2} + 3xy + y ^{2} = 3 ^{2} + (3 \times 3 \times 4) + 4 ^{2} = 9 + 36 + 16 = 61$