Question

defrenciate it by chain rule​

Answer 1

Answer:

1/xlogx

Step-by-step explanation:

z = x²

y = log(log z)

let log z = t

hence y = log t

dy/dx = dy/dt × dt/dz × dz/dx

dy/dx = (1/log x²)×(1/x²)×(2x)

= 2/(xlogx²) = 1/xlogx [ using log properties]