Math, asked by mohammadarifzaki, 7 months ago

degree of (x) in 6x²x³​

Answers

Answered by sid77776
6

Answer:

Hey mate

Step-by-step explanation:

Degree is 3

Hope it helps

Answered by sarojiniaind6
2

Answer:

the degree of a polynomial is the highest of the degrees of the polynomial's monomials (individual terms) with non-zero coefficients. The degree of a term is the sum of the exponents of the variables that appear in it, and thus is a non-negative integer. For a univariate polynomial, the degree of the polynomial is simply the highest exponent occurring in the polynomial.[1][2] The term order has been used as a synonym of degree but, nowadays, may refer to several other concepts (see order of a polynomial (disambiguation)).

For example, the polynomial {\displaystyle 7x^{2}y^{3}+4x-9,}{\displaystyle 7x^{2}y^{3}+4x-9,} which can also be written as {\displaystyle 7x^{2}y^{3}+4x^{1}y^{0}-9x^{0}y^{0},}{\displaystyle 7x^{2}y^{3}+4x^{1}y^{0}-9x^{0}y^{0},} has three terms. The first term has a degree of 5 (the sum of the powers 2 and 3), the second term has a degree of 1, and the last term has a degree of 0. Therefore, the polynomial has a degree of 5, which is the highest degree of any term.

To determine the degree of a polynomial that is not in standard form, such as {\displaystyle (x+1)^{2}-(x-1)^{2}}{\displaystyle (x+1)^{2}-(x-1)^{2}}, one can put it in standard form by expanding the products (by distributivity) and combining the like terms; for example, {\displaystyle (x+1)^{2}-(x-1)^{2}=4x}{\displaystyle (x+1)^{2}-(x-1)^{2}=4x} is of degree 1, even though each summand has degree 2. However, this is not needed when the polynomial is written as a product of polynomials in standard form, because the degree of a product is the sum of the degrees of the factors.

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