Question

DEN Ovisor and the original divista
3
3
1
I
1
1
144)2521
Prelor tres
of any two nur
100) 1441
109
Last divisor 36108
36) 100 (
108
0
So, the HCP of 144 and 252 is 36
Ruler Divide the master by common factors o solution 1 First, we take 190 and 171 and find their HC
171)1901
Find the product of the common factor
171
Now, we find the
netor excepi 1. so siop dividing
19717160
0
The HCP of 190 and 171 is 19.
So, the HCP
the process until you get the remainder
Step 3: The last divisor is the required HCP.
Erample 5: Find the HCP of 144 sand 252.
Example 61 Find the IICF of 190, 171 and 152.​

Answer 1

Answer:

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