Question

Denominator of a number is 4 less than it's denominator. If 6 is added to the numerator, it becomes thrice the denominator. Find the fraction.

Answer 1

Answer:

let the numerator be x

so denominator=x-4

original fraction=x/x-4

6 is added to the numerator

so it becomes thrice the denominator

so x+6=3(x-4)

=x+6=3x-12

=3x-12=x+6

=(3x-x)=6-12

=2x= -6

=x= -6/2

=x= -3

Answer 2

Solution : (Question Error)

$\bf{\red{\underline{\underline{\bf{Given\::}}}}}$

Denominator of a number is 4 less than it's numerator. if 6 is added to the numerator,It becomes thrice the denominator.

$\bf{\red{\underline{\underline{\bf{To\:find\::}}}}}$

The fraction.

$\bf{\red{\underline{\underline{\bf{Explanation\::}}}}}$

Let the numerator be r

Let the denominator be m

$\therefore\boxed{\bf{The\:fraction=\dfrac{r}{m} }}}$

A/q

$\leadsto\bf{m=r-4....................(1)}$

&

$\leadsto\sf{r+6=3m}\\\\\leadsto\sf{r+6=3(r-4)\:\:\:\:[from(1)]}\\\\\leadsto\sf{r+6=3r-12}\\\\\leadsto\sf{r-3r=-12-6}\\\\\leadsto\sf{-2r=-18}\\\\\leadsto\sf{r=\cancel{\dfrac{-18}{-2} }}\\\\\leadsto\sf{\green{r=9}}$

Putting the value of r in equation (1),we get;

$\leadsto\sf{m=9-4}\\\\\leadsto\sf{\green{m=5}}$

Thus;

$\boxed{\bf{The\:fraction\:=\dfrac{r}{m} =\dfrac{9}{5} }}}}}$