Density of 2 m aqueous solution of naoh is 1.28 g/cm3. The molality of the solution is [given that molecular mass of naoh = 40 g molâ1]
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Explanation:
As we know the famous relation between molarity and molality we could solve it very quickly.
Let's see
m= 1000M /1000d-MM2
Where
m---> Molality
M----> Molarity
d----> density of solution in g/ml
M2---> Molar mass of solute (here is 23+16+1=40)
So m= 1000 * 2/1000*1.28 - 2*40
=2000/1200
= 5/3
=1.66667m
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