Question

Density of 5 molal NaOH solution is 1.1gml-1 . Calculate the normality and molarity of the solution​

Answer 1

Answer:

2.97M

Explanation:

Molality of NaOH solution =3 m

Molality=number of moles of solute/mass of solvent(kg)

3=

massofsolvent

n

mass of solvent =

3

1000n

g

Also, number of moles=mass/molar mass

For NaOH solution, n=

40

m

Density of solution,ρ=1.110g/mL

Mass of 1 mL solution =1.11g=m

solute

+m

solvent

3

n×40+1000n=1.11

n=2.97×10

−3mol

Molarity = number of moles of solute/ volume of solution(L)

M= 0.001

2.97×10 −3

=2.97M