if the first term of G.P is 729 and 7th term is 64, find the sum of 7 terms
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Step-by-step explanation:
The nth term of a Geometric Progression is given by the formula
T(n)=a∗r(n−1)
Sum of n terms of a Geometeric Progression is given by the formula
S(n)=a(1−r(n−1))/(1−r)
Here 'a' is the first term and 'r' is the common difference.
If you know the above formulas, then solving this question should be pretty simple. We are given
a = 729
T(7) = 64
=> ar^(7-1) = 64
=> 729*r^6 = 64
=> r^6 = 64/729 = (2/3)^6
=> r = 2/3
Now, we need to find out the sum of the first 7 terms
S(7) = 729 * (1 - (2/3)^6) / (1-2/3)
=> S(7) = 729 * ( (729-64) / 729) / (1/3) )
=> S(7) = 729 * (665/243)
=> S(7) = 1995
So, the sum of the first 7 terms of the Geometric Progression (GP) is 1995
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