Question

density of a 2.50 molar solution of Acetic acid in water is 1.02 gram per ml the molality of the solution is ​

Answer 1

Answer:

molality= mole of solute/weight of solvent(kg).

Answer 2

Answer:

  m = 2.285mol kg⁻¹

Explanation:

molality - m

molarity - M

Density - d

M₂ - Molecular mass - CH₃COOH = 60g

m = 1000M / 1000d - MM₂

m = 1000 × 2.05 / (1000 × 1.02) - (2.05 × 60)

m = 2050 / 1020 - 123

m = 2050 / 897

m = 2.285mol kg⁻¹