Question

Density of ethanol at room temperature is 0.92 g cm ^-3. How many molecules are present in 1 mL of ethanol ?

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Answer 1

Mass of 1 mL of ethanol = Volume × Density = 1.0 cm^3 × 0.92 g cm ^-3

= 0.92 g

Number of molecules =

$\frac{0.92 \: g}{46 \: g \: mole ^{ - 1} } = 0.02 \: mole$

Number of molecules =

$0.02 \times 6.02 \times 10 ^{23} \\ = 1.204 \times 10 ^{22} molecules$

Answer 2

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