Question

density of gold is 19.3g/cm^3. Express it in kg/m^3

Answer 1

DENSITY OF GOLD IS 19.3/G/CM 3
DENSITY IN KG/M3
1 KG/M^3 =1000G/10 ^6CM^3
1KG/M^3 = 10^-3 G/CM^3
10^-3 G/CM^3 = 1 KG /M ^3
19.6 G/M^3 = 19.6 × 10^-3
19.5 G/M^3 = 19600KG/M^3

Answer 2

The density of gold is 19,300kg/m³.

Given:

Density of gold= 19.3g/cm³

To Find:

The density of gold in kg/m³

Solution:

We know that,

1 kg= 1000g

So, 1g= 1/1000 kg

1m= 100cm

So, 1cm= 1/100m

And, 1cm³= 1/(100)³ m³

So, we can now convert the units as follows.

Density of gold= 19.3g/cm³

$=19.3 X \frac{1}{1000}X 100^{3}kg/m^{3}$

=19,300 kg/m³

Therefore, the density of gold is 19,300kg/m³.

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