Question

density of mercury is 13.6 g/cm^3 calculate the no. of moles present in 1l of mercury ​

Answer 1

Answer:-

68 moles

Explanation:-

Given:-

→ Density of Mercury = 13.6g/cm³

→ Volume = 1L

To find:-

→ No of moles

Solution:-

=> 1L = 1000mL

Now, we know that 1mL = 1cm³

Hence, given volume of Mercury is:-

= 1×1000

= 1000cm³

Mass = Volume × Density

=> Mass = 13.6×1000

=> Mass = 13600g

• Molar mass of Mercury = 200g

No of moles = Given Mass/Molar mass

= 13600/200

= 68 moles

Thus, 68 moles are present in 1L of Mercury.