Density of oxygen
at 2 bar 42 degree celcius is
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Answer:
We know,
ρ=
R×T
P×molar mass
Here,
P=2 atm, Molar mass =32 g mole
−1
,T=300K, R=0.082
K−mol
L−atm
On substituting these values we get,
ρ=2.6g/L
Explanation:
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