Question

derivate the equation that weight of moon is1/6th part of earth​

Answer 1

Answer:

Explanation:

Suppose a body of mass "m" and its weight on the moon is Wm (where W is the weight and "m" is the moon;which means weight on the moon).Mass of the moon is "M"

and its radius is "R"

Weight of an object on the moon = "F"(Force)with which the moon pulls.

Wm = GM*m/r2

Weight of the same object on the earth is We(where W is the weight and "e" is the earth;which means weight on the earth).

Mass of the earth is 100 times of that of the moon.

Radius of the moon = R

Radius of the Earth = 4R

Weight of the object on the moon =

We = G100M*m/(4R)2(Pronounced 4 R square)

We = G100M*m/(16R)2(Pronounced 16 R square)

Wm/We = G * M * m * 16R2/R2 * g * 100M * m

=16/100

Wm/We = 16/100 =1/6

Weight on the moon is 1/6 weight on the earth.(Hence Derived).

Answer 2

Explanation:

let mass of the.moon be 'm' and its radius be r .let an object of.mass m be lying on its surface.

1. according to the universal law of gravitaton, wight of object on the moon ,Wm=GMm/R square.
2. we know that,mass of the earth is about 100 times greater than the mass of moon and its radius is 4 times greater than the radius of the moon