The base of an isosceles triangle is 4/3 cm. The perimeter of the triangle is NCERT Solution For Class 8 Maths Chapter 2 Image 1 cm. What is the length of either of the remaining equal sides?
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Answered by
4
Answer:
ʜᴇʀᴇ ɪs ʏᴏᴜʀ sᴏʟᴜᴛɪᴏɴ..
ʙᴀsᴇ=4/3ᴄᴍ.
ʟᴇᴛ ᴛʜᴇ ᴇǫᴜᴀʟ sɪᴅᴇs ʙᴇ x.
ᴘᴇʀɪᴍᴇᴛᴇʀ=S1+S2+S3
62/15=x+x+4/3
62/15=2x+4/3
62/15-4/3=2x
(62-20)/12=2x
42/15/2=x
42/15×1/2=x
21/15=x
7/5=x
Tʜᴜs,
Tᴡᴏ ᴇǫᴜᴀʟ sɪᴅᴇs=x=7/5ᴄᴍ.
ʜᴏᴘᴇ ɪᴛ's ʜᴇʟᴘs ᴜ✔︎
Step-by-step explanation:
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Answered by
0
Answer:
7/5 cm
Step-by-step explanation:
Base of isosceles triangle = 4/3 cm
Perimeter of triangle = 62/15 cm
Let the length of equal sides of triangle be x.
According to the question,
4/3 + x + x = 62/15 cm
⇒ 2x = (62/15 – 4/3) cm
⇒ 2x = (62 – 20)/15 cm
⇒ 2x = 42/15 cm
⇒ x = (42/30) × (½)
⇒ x = 42/30 cm
⇒ x = 7/5 cm
The length of either of the remaining equal sides are 7/5 cm.
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