Question

derivation for moment of inertia of uniform circular ring about an Axis passing through its centre and perpendicular to its plane​

Answer 1

Answer:

See the proof below

Explanation:

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The mass of the disc is

=

M

The density is

=

ρ

The radius of the disc is

=

R

We start with the definition

d

I

=

ρ

r

2

d

V

ρ

=

M

V

d

i

s

k

=

M

π

r

2

h

V

=

π

r

2

h

d

V

=

2

π

r

h

d

r

I

=

M

π

r

2

h

∫

R

0

r

2

(

2

π

h

r

d

r

)

=

M

π

r

2

h

⋅

2

π

h

∫

R

0

r

3

=

2

M

r

2

[

r

4

4

]

R

0

=

1

2

M

R

2

Answer 2

if you cannot see digram

so see it on NCERT PHYSICS TEXTBOOK

pg no. 166

Fig 7.13

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