Question

derivation of 1st equation of motion by graphical method

Answer 1

tanθ = AB
          BC
     a = v-u
            t
    at = v-u
      v = u+at

Answer 2

$\textbf{\large{Answer -}}$

Since, we know that the slope or gradient of $v-t$ graph shows acceleration. Therefore,

=> $a = tan {\theta}$

or, $\frac {BC}{AC}$

or, $\frac {BD-CD}{OD}$

or, $\frac {BD-OA}{OD}$

or, $a = \frac {v-u}{t}$

$\boxed{\textbf{v = u + at}}$