Question

Derivation of 3 types of graph​

Answer 1

Answer:

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Three types of graphs are used in this course: line graphs, pie graphs, and bar graphs. Each is discussed below.

The following are the three equation of motion:

The following are the three equation of motion:First Equation of Motion: v = u + at.

The following are the three equation of motion:First Equation of Motion: v = u + at.Second Equation of Motion: s = ut + 1/2(at2)

The following are the three equation of motion:First Equation of Motion: v = u + at.Second Equation of Motion: s = ut + 1/2(at2)Third Equation of Motion: v2 = u2 – 2as

Answer 2

We know that the acceleration of the body is defined as the rate of change of velocity.

Mathematically, acceleration is represented as follows:

a=v−ut

where v is the final velocity and u is the initial velocity.

Rearranging the above equation, we arrive at the first equation of motion as follows:

v=u+at

The total distance travelled, s is given by the Area of trapezium OABC.

Hence,

S = ½ (Sum of Parallel Sides) × Height

S=(OA+CB)×OC

Since, OA = u, CB = v, and OC = t

The above equation becomes

S= ½ (u+v) × t

Now, since t = (v – u)/ a

The above equation can be written as:

S= ½ ((u+v) × (v-u))/a

Rearranging the equation, we get

S= ½ (v+u) × (v-u)/a

S = (v2-u2)/2a

Third equation of motion is obtained by solving the above equation:

v2 = u2+2aS

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