derivation of 3rd equation of motion
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Hi there,
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derv... of v²=u²+2as
v= final velocity
u=initial velocity
a=acceleration
s=displacement
so... basic.... we know .... v = ds/dt (obviously)
speed = disp/tim
and a = dv/dt
acceleration = (change in) velocity/unit time
=> a = dv/dt x ds/ds
and bcause ds/dt = v
we get
a=v dv/ds
=>
v dv = a ds
now (integration)
(v²-u²)/2 = as
=> v²=u²+2as
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Cheers
:)
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