Derivation of first and Second Equation of motion ?
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✴) First equation of Motion: V = u + at soln. Consider a body of mass “m” having initial velocity “u”.Let after time “t” its final velocity becomes “v” due to uniform acceleration “a”. Now we know that: Acceleration = change in velocity/Time taken => Acceleration = Final velocity-Initial velocity / time taken => a = v-u /t =>at = v-u or v = u + at
✴) Second Equation of Motion :
Let the distance travelled by the object be “s”.
We know that,
→Distance = Average velocity × time
→Average velocity = (u+v)/2
Then s=(u+v)/2×t
According to first equation if motion,
v = u + at
substituting the value of v in above equation
s = (u+u+at)/2 x t
→s = (2u+at)/2 × t
→s = (2ut+at²)/2
→s = 2ut/2 + at²/2
→s=ut+1/2at²
Hence derived.
Hope it helps you out ✴^_^✴
Thanks ⭐(^^)⭐
✴) First equation of Motion: V = u + at soln. Consider a body of mass “m” having initial velocity “u”.Let after time “t” its final velocity becomes “v” due to uniform acceleration “a”. Now we know that: Acceleration = change in velocity/Time taken => Acceleration = Final velocity-Initial velocity / time taken => a = v-u /t =>at = v-u or v = u + at
✴) Second Equation of Motion :
Let the distance travelled by the object be “s”.
We know that,
→Distance = Average velocity × time
→Average velocity = (u+v)/2
Then s=(u+v)/2×t
According to first equation if motion,
v = u + at
substituting the value of v in above equation
s = (u+u+at)/2 x t
→s = (2u+at)/2 × t
→s = (2ut+at²)/2
→s = 2ut/2 + at²/2
→s=ut+1/2at²
Hence derived.
Hope it helps you out ✴^_^✴
Thanks ⭐(^^)⭐
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thanku so much bhai
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