Physics, asked by Anonymous, 1 year ago

Derivation of first and Second Equation of motion ?
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Answered by batradivjyot25
1
Here is your answer....

✴) First equation of Motion: V = u + at soln. Consider a body of mass “m” having initial velocity “u”.Let after time “t” its final velocity becomes “v” due to uniform acceleration “a”. Now we know that: Acceleration = change in velocity/Time taken => Acceleration = Final velocity-Initial velocity / time taken => a = v-u /t =>at = v-u or v = u + at

✴) Second Equation of Motion :
Let the distance travelled by the object be “s”.

We know that,

→Distance = Average velocity × time

→Average velocity = (u+v)/2

Then s=(u+v)/2×t

According to first equation if motion,
v = u + at
substituting the value of v in above equation

s = (u+u+at)/2 x t

→s = (2u+at)/2 × t

→s = (2ut+at²)/2

→s = 2ut/2 + at²/2

→s=ut+1/2at²

Hence derived.

Hope it helps you out ✴^_^✴
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Anonymous: thanku so much bhai
Answered by Anonymous
1
hope this helps you......
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