Question

Derivation of Pythagoras Theorem? Answer should be simple and well explain?​

Answer 1

In a right triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides of the triangle.

In a right triangle, side opposite to the 90° is always the hypotenuse. The square of the side opposite of the 90° in a right triangle is equal to the sum of squares of the other two sides.

∆ ABC is a right triangle, right angled at B. Here, AC is the hypotenuse of the right ∆ ABC.

So, the square of AC is equal to the sum of the squares of the other two sides AB and BC.

I.e., AC2 = AB2 + BC2 (Pythagoras Theorem)

Hope it helps ✔✔✔