Derivation of s=ut+1/2at^2
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s=area OABC(which is a trapezium) = area of the rectangle OADC+area of the triangle ABD
=OA*OC+1/2(AD*BD)
Substituting OA =u, OC =AD=t and BD = at, we get,
s=u*t+1/2(t*at)
s=ut+1/2 at ka square
=OA*OC+1/2(AD*BD)
Substituting OA =u, OC =AD=t and BD = at, we get,
s=u*t+1/2(t*at)
s=ut+1/2 at ka square
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