DERIVATIONS
series
parellel
heating
electric
Answers
SERIES
in series applied potential produces current and causes a potential drop ie. V1,V2,V3 across R1,R2,R3
therefore,
V=V1+V2+V3
OHMS LAW - V=IR
V1=IR1
V2=IR2
V3=IR3
FROM ABOVE
IR= IR1 + IR2 + IR3
IR= I (R1+R2+R3)
I - I GETS CANCEL
IE... Rs= R1 + R2 + R3
==============================================================
PARELLEL COMBINATION
APPLIED POTENTIAL PRODUCES CURRENT
I = i1 +i2 +i3
OHMS LAW - i = v/r
V/R = V/R1 + V/R2 +V/R3
V/R = V(1/R1 + 1/R2 + 1/R3)
V-V GETS CANCLE
1/RP = 1/R1 + 1/R2 + 1/R3
=============================================================
HEATING
W = VQ (POTENTIAL DIFFERENCE)
Q=IT (CURRENT DEFINATION)
PUTING VALUE
W = VIT
W = I2RT (V=IR)
W = H ( ASSUMING )
H= I2RT
=============================================================
ELECTRIC POWER
power = W/T
P = VIT/T ( AS W=VIT)
T - T GETS CANCLE
P = VI
==============================================================
HERE ARE ALL UR DERIVATIONS HOPE IT HELPS
MARK BRAINLIEST PLEASE
Answer:
In series combination, resister are connected end to end and current has a single path through the circuit but the potential difference varies across each resistor. Thus we can write as,
V = V1 + V2 + V3
according to Ohm's law V = IR So,
V1 = I R1, V2 = I R2, V3 = I R3
V = I R1 + I R2 + I R3
V = I(R1+R2+R3)
V =IRe
All the individual resistances become equal to the equivalent resistance.
or Re = R1 + R2 + R3......Rn
In parallel combination, each resistor'sone is connected to the positive terminal while the other end is connected to a negative terminal. The potential difference across each resistance is the same and the current passing through them is different.
V = V1 =V2=V3
I = I1+ I2+I3
Current throught each resistor will be:
I1= V/R1 , I2 = V/R2 = I3 = V/R3
I = V (1/R1+ 1/R2+1/R3)
In case of equivalent resistance I=V/Re
V/Re = V (1/R1+ 1/R2+1/R3)
So the equivalnet resistance is the sum of all resistances
1/Re = 1/R1+ 1/R2+1/R3