Math, asked by kjajkskdndnkdk, 1 year ago

derivative of f(x)=x^2sinx +sin^2x

Answers

Answered by abhiranjan1
1
2xsinx + x^2cosx +2sinx.cosx
2xsinx + x^2cosx +sin2x
Answered by atul103
0
d/dx(x2sinx)=

d/dx(x2)⋅sinx+x^2⋅ddx(sinx)=

2xsinx+x2cosxdd⁡x(x2sin⁡x)=

d/d⁡x(x^2)⋅sin⁡x+x^2⋅dd⁡x(sin⁡x)=

2xsin⁡x+x^2cos⁡x

This is because of the product rule.
hope it's helpful for you
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