derivative of f(x)=x^2sinx +sin^2x
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Answered by
1
2xsinx + x^2cosx +2sinx.cosx
2xsinx + x^2cosx +sin2x
2xsinx + x^2cosx +sin2x
Answered by
0
d/dx(x2sinx)=
d/dx(x2)⋅sinx+x^2⋅ddx(sinx)=
2xsinx+x2cosxddx(x2sinx)=
d/dx(x^2)⋅sinx+x^2⋅ddx(sinx)=
2xsinx+x^2cosx
This is because of the product rule.
hope it's helpful for you
d/dx(x2)⋅sinx+x^2⋅ddx(sinx)=
2xsinx+x2cosxddx(x2sinx)=
d/dx(x^2)⋅sinx+x^2⋅ddx(sinx)=
2xsinx+x^2cosx
This is because of the product rule.
hope it's helpful for you
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