Question

derivative of sec under root x square +9​

Answer 1

Answer:

Step-by-step explanation:

$\frac{d}{dx} sec\sqrt{x^{2} +9} \\sec\sqrt{x^{2}+9 } tan\sqrt{x^{2}+9 } \frac{d}{dx} \sqrt{x^{2}+9}\\\\sec\sqrt{x^{2}+9 } tan\sqrt{x^{2}+9 } \frac{1}{2\sqrt{x^{2} }+9 } \frac{d}{dx} (x^{2} +9)\\sec\sqrt{x^{2} +9} tan\sqrt{x^{2}+9 } \frac{1}{2\sqrt{x^{2}+9 } }2x$