Question

derivative of Sin inverse 2x

Answer 1

Hi!!!

Derivative of Sin inverse 2x is


1 / √ ( 1 - 2x)²) × 2

by chain rule of differentiation.

Answer 2

by using the chain rule,

$\frac{d(arcsin(2x))}{dx} *  \frac{d(2x)}{x}$

$\frac{1}{\sqrt{1-4x^2}}  * 2$

$\frac{2}{\sqrt{1-4x^2}}$