derivative of sin^n x
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use
y=x^n
dy/dx=n.x^(n-1)
now
y=sin^nx
dy/dx=n.sin^(n-1) x.d (sinx)/dx
=n.sin^(n-1) x.cosx
y=x^n
dy/dx=n.x^(n-1)
now
y=sin^nx
dy/dx=n.sin^(n-1) x.d (sinx)/dx
=n.sin^(n-1) x.cosx
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