derivative of tan[log (sin x)]
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Hi it is your answer
dy/dx= (1/sin x)*d(sin x)/dx= cos x/sin x= cot x. It is a simple application of the chain rule . Using this , f(x) = Log (x) and g (x) is sin x. and in the question above we considered log as “f” and sin as “g”.
dy/dx= (1/sin x)*d(sin x)/dx= cos x/sin x= cot x. It is a simple application of the chain rule . Using this , f(x) = Log (x) and g (x) is sin x. and in the question above we considered log as “f” and sin as “g”.
surajchadri:
answer is wrong
kaise
log ke pehla tanx ha jiska differentiation nahi kia ho
ohho
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