Question

derivative of tan2x+3

Answer 1

dtan2x+3/dx=(dtan2x+3/d2x+3)x(d2x+3/dx)=
sqr(sec) 2x+3 x 2=
2sqr(sec)2x+3

Answer 2

Answer:

2sec^2(2x)+d(3)dx =› 2sec^2(2x)+0=2sec^2(2x)

Step-by-step explanation:

Assuming that you know the derivative rule: d/dx(tanx)=sec2(x)

d/dx(tan(2x)) will simply be sec2(2x)⋅d/dx(2x) according to the chain rule.

Then d/dx(tan(2x))=2sec2(2x)

If you want to easily understand chain rule, just remember my tips: take the normal derivative of the outside (ignoring whatever is inside the parenthesis) and then multiply it by the derivative of the inside (stuff inside the parenthesis)

anyway costant derivative is 0