Question

derivative of xcosx/x+tanx​

Answer 1

Answer:

-sin x + $sec^{2}x$

Step-by-step explanation:

since its xcosx/x the numerator x and denominator x will get cancelled and we will be left with cos x + tan x.

so d/dx(cos x) + d/dx(tan x) which is equal to

    -sin x       +    $sec^{2}x$