Question

Derivative of Y= (ax+b)^2 Please someone

Answer 1

I don't know

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Answer 2

Step-by-step explanation:

Integral of x^n = x^(n+1) / (n+1)

So, Integral of (ax+b)^2 is as follows:

Now, let (ax+b) = y

So, Integral of y^2 = y^3 / 3

Now, substitute the value of y : (ax+b)^3 / 3

Now, since the integral of (ax+b)^n = {[(ax+b)^(n+1) / (n+1)] x 1/a} +c ,

Your final answer will be = {[(ax+b)^3 / 3] x 1/a} +c