Question

derivative of y=cos^-1(2x/(1+x^2) put x=tan teeta

Answer 1

Step-by-step explanation:

y = cos^-1 [ 2x/(1+x²) ]

x = tan@

y = cos^-1 [ 2tan@/(1+tan²@) ]

y = cos^-1 [ sin2@ ]

y = cos^-1 [ cos(π/2 - 2@) ]

y = π/2 - 2@

y = π/2 - 2(tan^-1(x) )

dy/dx = -2/1+x²