Question

derivatives ofd/dx of tanx.secx​

Answer 1

Step-by-step explanation:

$\bold{\frac{d}{dx}(tanx.secx)}$

Formula -

$\bold{If \: y = u.v \: \: then - }$

$\bold{ \frac{dy}{dx} = u. \frac{dv}{dx} + v.\frac{du}{dx} }$

$\implies \bold{\frac{d}{dx}(tanx.secx)}$

$\bold{ \scriptsize{ \implies{tanx. \frac{d}{dx}(secx) + secx. \frac{d}{dx}(tanx)}}}$

$\bold{ \scriptsize{ \implies{tanx(secx.tanx) + secx( {sec}^{2} x)}}}$

$\bold{ \scriptsize{ \implies{secx.tan^{2}x + secx( {sec}^{2} x)}}}$

$\bold{ \scriptsize{ \implies{secx(tan^{2}x + {sec}^{2} x)}}}$

I hope it is helpful