Derive. 1st and 2nd equation of motion
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we know a = (v-u)/t
at=v-u
v=u+at ....... eq.1
We also know
s=v×t v=u+at
s= (v+u)/2 ×t
s=(2u+t)2 ×t
s= ut+1/2 at^2
at=v-u
v=u+at ....... eq.1
We also know
s=v×t v=u+at
s= (v+u)/2 ×t
s=(2u+t)2 ×t
s= ut+1/2 at^2
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