Physics, asked by adityarexyyuvi, 7 months ago

Derive a relationship between position and time​

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Answered by piyushsahu624
0

Answer:

Consider the graph shown in the given attachment. Obviously, the total distance s travelled by the object in time t is given by are under v-t graph. Obviously, OABGC is a trapezium, whose area is (OA + BC/2) × OC. Therefore, this equation is the position velocity relation for uniformly accelerated motion.

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