Chemistry, asked by prachi71204, 3 months ago

derive an equation for solubility product of silver chromate​

Answers

Answered by Anonymous
7

Explanation:

Ag2CrO4 ==> 2Ag+ + CrO4 2-Ksp = [Ag+]2 [CrO4 2-] = (2x)^2 (x) = 4x^3 = 1.1 x 10^-12 x^3 = 2.8 x 10^-13 the value for the Ksp of silver chromate is reported to be 1.1 x 10^-12. Ksp is only used for slightly insoluble salts.

Answered by Anonymous
1

Answer:

Hey mate⚡

Explanation:

Ag2CrO4 ==> 2Ag+ + CrO4 2-Ksp = [Ag+]2 [CrO4 2-] = (2x)^2 (x) = 4x^3 = 1.1 x 10^-12 x^3 = 2.8 x 10^-13 the value for the Ksp of silver chromate is reported to be 1.1 x 10^-12. Ksp is only used for slightly insoluble salts.

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