derive an equation of kinetic energy calculate the work required to be done to stops car of 1500kg moving at the velocity of 6okm/h
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Kinetic energy=1/2*m*v ^2
=1/2*1500*60*60
=270000J
Work done =change in Kinetic energy
Final velocity=0
Final K. E-initial k. E =0-270000
=270000J
Hope it helps you
Mark it as the brainest pleaseeeeeeee
=1/2*1500*60*60
=270000J
Work done =change in Kinetic energy
Final velocity=0
Final K. E-initial k. E =0-270000
=270000J
Hope it helps you
Mark it as the brainest pleaseeeeeeee
Sangaychodenlepcha:
brainest
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