Derive an experiment for the equivalent resistance of a combination of a three resistance connected in parallel
Answers
Explanation:
■⇨Let's take the above circuit in the experiment so for the equilavent reisitance expression as follows ⇩⇩⇩⇩⇩⇩⇩⇩⇩⇩⇩⇩⇩⇩
●We know the current flowing through all the reisitances is different but te sum of the current flowin through all the resistances is equal to the total current supplies by a battery or cell .
◆So Let I be the total current and the current flowing through R¹ ,R² and R³ be I¹,I² and I³.
•°• I = I¹ + I² + I³.........(1)
Now from ohms law we get :-
→I = V/R.........(2)
Now let's apply ohms law for all the resistances we get;
→I¹=V/R¹........(3)
→I²=V/R².......(4)
→I³=V/R³........(5)
Now put the value of I, I¹,I² and I³ in the first equation
→I = I¹+I²+I³
→V/R= V/R¹ + V/R² + V/R³
→V(1/R) =V (1/R¹ + 1/R² + 1/R³)
cancalling V at both sides -
→1/R=1/R¹ + 1/R² + 1/R³
is the expression for calculation equavelent resistances connected in parallal. ✔✔