Question

derive an expression for elastic potential energy of a spring ​

Answer 1

Answer:

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Explanation:

Hooke’s Law, F = -kx, where F is the force and x is the elongation.

The work done = energy stored in stretched string = F.dx

The energy stored can be found from integrating by substituting for force,

and we find,

The energy stored = kx2/2, where x is the final elongation.

The energy density = energy/volume