derive an expression for electric energy consumed in a device in terms of v,i and t where v is the potential difference applied to it,I is the current drawn by it and t is the time for which current flows?
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Answered by
1
We know
W = Q*V ..............(1) where W = Work done, Q = flow of charges and V = potential difference
We also know
Current I = Q/t where Q = flow of charges and t = time
= Q = It............(2)
putting value of Q from equation (2) to (1)
Work done or energy consumed = V*I*T
W = Q*V ..............(1) where W = Work done, Q = flow of charges and V = potential difference
We also know
Current I = Q/t where Q = flow of charges and t = time
= Q = It............(2)
putting value of Q from equation (2) to (1)
Work done or energy consumed = V*I*T
Answered by
1
Explanation:
Energy =( V²/R²)t
We know that work done ,
W=QV
.•. P=W/t
now,
P=QV/t
V=IR
P=(Q/t)I²R
=I²R
Energy =P×t
=I²R×t
=(V²/R²)×R×t
=(V²/R)t
energy=(V²/R)t
where,V=voltage
R = resistance
t=time
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