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There are 366 days In leap year
Now
52 weeks * 7 days/week = 364 day
52 full weeks means -> 52 Friday
For remaining 2 days, one of the following pairs is possible
Monday - TuesdayTuesday - WednesdayWednesday - ThursdayThursday - FridayFriday - SaturdaySaturday - SundaySunday - MondayOut of 7 pair, there is 2 pair in which 53rd Friday may come.
Probability of 53 Friday in a leap year = 2÷7
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i think 2/7
1 leap year contain 52 weeks and 2 days.
sample space=(mon,tue) (tue,wed).....
n(s)=(7)
let A be the event of getting friday in a leap year
A=((thu,fri) (fri,sat))
n(A)=(2)
p(A)=n(A) ÷ n(s)
p(A)=2/7
1 leap year contain 52 weeks and 2 days.
sample space=(mon,tue) (tue,wed).....
n(s)=(7)
let A be the event of getting friday in a leap year
A=((thu,fri) (fri,sat))
n(A)=(2)
p(A)=n(A) ÷ n(s)
p(A)=2/7
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