Question

Derive an expression for electric field at a point through a linear charged conductor​

Answer 1

Answer:

s λ is charge per unit length of the conductor A, the net charge enclosed by the Gaussian cylinder is λl. ∴E=λ2πεr=λ2πε0kr, where k is the dielectric constant of the medium. This gives the magnitude of the electric field intensity in terms of the linear charge density λ.

Explanation:Hope it helps.

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Answer 2

Answer:

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Explanation:

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