Question

Derive an expression for finding stopping distance of vehicle moving with the initial speed V and breaking capacity 'a'.​

Answer 1

let stopping distance be s

initial velocity be u

stopping capacity or retardation be -a

by kinematics

${v}^{2} - {u}^{2} = - 2as \\ as \: v = 0 \\ = > - {u}^{2} = - 2as \\ = > {u}^{2} = 2as \\ = > s = \frac{ {u}^{2} }{2a}$

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