derive an expression for frictional force
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As discussed, the formula for frictional force is given by F = μN
Answer:
Assume a large block of ice is being pulled across a frozen lake. Furthermore, the mass of the block of ice is 250 kg. Also, the coefficient of friction between the two surfaces is small μk = 0.05. So, find the force of friction that acts on the block of ice?
Explanation:
The normal force of an object on a flat surface is η = mg. Also, by using this formula we can calculate the force of friction
Ff = μη
Ff = μ mg
Fk = (0.05) (250 kg) (9.8 m/s²)
Fk = 122.5 kg⋅m/s²
Fk = 122.5 N
Hence, the force of friction acting upon the block of ice while it is being pulled is 122.5 N.
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