Physics, asked by zararana020gmailcom, 6 months ago

derive an expression for horizontal range of projectile.

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Answered by gowtham73
3

Say an object is thrown with uniform velocity V0 making an angle theta with the horizontal (X) axis.

The velocity component along X-axis = V0x = V0 cosθ and the velocity component along Y-axis = V0y = V0sinθ. Air resistance is taken as negligible

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