Physics, asked by 10432samyuktha, 8 months ago

derive an expression for Joule ' s law of heating

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Answers

Answered by anusunkari9
1

Answer:

He determined that the heat evolved per second is equivalent to the electric power absorbed, or the power loss. A quantitative form of Joule's law is that the heat evolved per second, or the electric power loss, P, equals the current I squared times the resistance R, or P = I2R.

Answered by Anonymous
7

\underline\mathrm\blue{Joule's \: law \: of \: heating \: :-}

\sf H \: = \: I^{2}Rt.

Derive the joule's law of heating :

\sf W \: = V \times Q ----------- (i)

Form the above expression,

\sf V \: = \: \dfrac {w}{Q}

Now,

We know that V = IR ---------- (ii)

Q = It ----------- (iii)

Therefore,

Here, \sf Current \: = \: \dfrac {Charge}{time}

Let's substitute eq (ii) & (iii),

We get,

W = (IR)(It)

let's multiply the both brackets,

We get,

\sf W \: = \: I^{2}Rt

W = H.

Here, H is the heat produced.

\therefore \sf H \: = \: I^{2}Rt

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