Math, asked by adityasingh6584, 9 months ago

the area of two equal circles in the figure is 308 cm. find the area of the rectangle ​

Answers

Answered by niishaa
7

Answer:

area of rectangle = 98 cm²

Step-by-step explanation:

Area of two equal circles is 2 x πr²

=> 2 x 22/7 x r x r = 308

=> r² = 308/2 x 7/22

=> r² = 49

=> r = √49

= 7 cm

Now,

2r = diameter of circle = length of rectangle length=14 cm

radius of circle = breadth of rectangle=7 cm

therefore,

area of rectangle = length× breadth

= 14 × 7

= 98 cm²

area of rectangle = 98cm²

\huge\boxed{\fcolorbox{black}{yellow}{Hope it helps}}

Answered by matangidevi198597
2

\sf\huge\underline{Answer :-}

Answer:−

Given :

Area of two equal circles = 308 cm²

To find :

Area of the rectangle

Solution :

\sf Area \: of \: two \: circles \: = \: 308 \: {cm}^{2}Areaoftwocircles=308cm

2

\sf \therefore Area \: of \: one \: circle \: \rightarrow \dfrac{308}{2} = 154 {cm}^{2}∴Areaofonecircle→

2

308

=154cm

2

\sf\longrightarrow \pi {r}^{2} = 154 {cm}^{2}⟶πr

2

=154cm

2

\sf\longrightarrow \dfrac{22}{7} {r}^{2} = 154⟶

7

22

r

2

=154

\sf\longrightarrow {r}^{2} = 154 \times \dfrac{7}{22}⟶r

2

=154×

22

7

\sf\longrightarrow {r}^{2} = {\cancel {154}} \times \dfrac{7}{{\cancel {22}}}⟶r

2

=

154

×

22

7

\sf\longrightarrow {r}^{2} = 7 \times 7⟶r

2

=7×7

\sf\longrightarrow {r}^{2} = 49⟶r

2

=49

\sf\longrightarrow r = \sqrt{49}⟶r=

49

\sf\longrightarrow r = 7⟶r=7

.°. Radius of one circle is = 7 cm

Diameter of one circle => Breadth of the rectangle = (2 × 7) cm = 14 cm

Diameter of two circles => Length of the rectangle = (14 × 2) cm = 28 cm

Now,

\sf\underline {Area \: of \: rectangle \: = \: (length \times breadth) \: {unit}^{2}}

Areaofrectangle=(length×breadth)unit

2

\sf\longrightarrow (14 \times 28) {cm}^{2}⟶(14×28)cm

2

\sf\therefore 392 {cm}^{2}∴392cm

2

Hence, the area of the rectangle is 392 cm².

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