Derive an expression for moment of inertia of a thin uniform disc about its transverse symmetry axis
Answers
Answered by
12
Answer:
Let us assume that disc is capable of rotating about a transverse axis passing through its centre. Let us assume that the disc is made up of infinitesimally thin rings. dI = 2 π t ρ r³ . ... This is an expression for moment of inertia of annular ring about a transverse axis passing through its centre
Answered by
4
Answer:
Let us assume that disc is capable of rotating about a transverse axis passing through its centre. Let us assume that the disc is made up of infinitesimally thin rings. dI = 2 π t ρ r³ . ... This is an expression for moment of inertia of annular ring about a transverse axis passing through its centre.
Similar questions