Physics, asked by akashraj93701, 8 months ago

Derive an expression for moment of inertia of a thin uniform disc about its transverse symmetry axis

Answers

Answered by vk5219167
12

Answer:

Let us assume that disc is capable of rotating about a transverse axis passing through its centre. Let us assume that the disc is made up of infinitesimally thin rings. dI = 2 π t ρ r³ . ... This is an expression for moment of inertia of annular ring about a transverse axis passing through its centre

Answered by viajaypkawle67
4

Answer:

Let us assume that disc is capable of rotating about a transverse axis passing through its centre. Let us assume that the disc is made up of infinitesimally thin rings. dI = 2 π t ρ r³ . ... This is an expression for moment of inertia of annular ring about a transverse axis passing through its centre.

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