Question

derive an expression for radius of bohr orbit of hydrogen atom​

Answer 1

Answer:

▶The borh radius { a0 or r Borh } is a physical constant , exactly to the most probable distance between the nucleus and the electron in a hydrogen atom in its around state. It is named after Niels Bohr , due to its role in the Bohr modal of an atom It's value is

5.29177210903{ 80 } ×10 - 11m.

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Answer 2

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YouR AnSwEr..!

According to Bohr’s model, the electron revolves revolve in stationary orbits where the angular momentum of electron is an integral multiple of h/2π.

mvr=nh/2pie

_______________ (1)

Here, h is Planck's constant.

Now, when an electron jumps from an orbit of higher energy E2 to an orbit of lower energy E1, it emits a photon. The energy of the photon is E2-E1. The relation between wavelength of the emitted radiation and energy of photon is given by the Einstein - Planck equation.

E2-E1= hf ____________ (2)

For an electron of hydrogen moving with a constant speed v along a circle of radius R with the center at the nucleus, the force acting on the electron according to Coulomb’s law is:

$f = e ^{2} \div 4\pi ε0r ^{2}$

The acceleration of the electron is given by v2/r. If m is the mass of the electron, then according to Newton’s law:

F=ma

$e ^{2} \div 4\pi ε0r ^{2} \\ = mv ^{2} \div r \\ = mv = (1 \div 4\piε0 \times me^{2} \div r) ^{1} \div^{2}$

_______________ (3)

From equation (1) and (3) we get,

For nth orbit,

https://school.gradeup.co/derive-an-expression-for-the-radius-of-nth-bohr-s-orbit-in-i-1nm1c7

Link ye hai xD... dekh lo... mere baski nhi ab edit krke likhna sry

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